math masters pay attention

1) if i dose 1 T of dry soda ash per day to my aquarium.
2) then mix 2 c of dry soda ash per gallon of ro/di water
3) how many ml/cc of that rodi/ash mix do i dose per day to meet the 1 T of dry ash?

 

I only have a math minor alongside my engineering major; sorry I can't help you.










Alright, fine.

118ml is the answer on a straight conversion. But I wouldn't be surprised if you find that's a bit too much now that you'll be adding it in a saturated solution (which won't face the precipitation issues adding it dry does). I'd start with half that and test daily, then adjust accordingly. Unless you already know what your Alk consumption is per day?

 

If I understand your question, you need 1/32 of a gallon or 3785/32 ml.

There are 16 tablespoons in a cup, so two cups is 32 tablespoons. A US gallon is 3785 ml.

Tablespoons and cups are not real precise however, so there will be some variability.

Edit: what he said.

 

correct, 118 cc/daily